Respuesta :

WojtekR
We have compound interests, so:

[tex]a_1=600\\\\r=4\%=0.04[/tex]

and:

[tex]A(n)=a_1(1+r)^{(n-1)}\\\\\boxed{A(n)=600(1+0.04)^{(n-1)}}\\\\\\A(5)=600(1+0.04)^{(5-1)}=600(1.04)^{4}=600\cdot1.17\approx\boxed{701.92}[/tex]

Answer B.