Respuesta :

mhanifa

[tex]\sqrt{p}[/tex]

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First, solve the inner radical:

  • [tex]\sqrt{p^{-2}} =p^{-2/2}=p^{-1}\\[/tex]

Now, simplify:

  • [tex]\sqrt{p^2*p^{-1}} =\sqrt{p^{2-1}} =\sqrt{p^1} =\sqrt{p}[/tex]

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