Respuesta :

Lilith
[tex]x = 11 ,\ \ \ A(11,0) \\ \\ x = 5 , \ \ \ B(5,0) \\ \\ distance \ between \ two \ parallel \ lines \ : \\ \\ d=\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}\\ \\d=\sqrt{(5-11)^2+(0-0)^2}=\sqrt{(-6)^2}=\sqrt{36}=6[/tex]
[tex]The\ distance:\\\\d=|11-5|=|6|=6[/tex]
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