Respuesta :

LammettHash
[tex]\tan5u\tan3u=\dfrac{\tan^24u\tan^2u}{1-\tan^24u\tan^2u}[/tex]

This is not true (assuming I've understood the question correctly).

Consider [tex]u=\dfrac\pi4[/tex]. Then

[tex]\tan\dfrac{5\pi}4\tan\dfrac{3\pi}4=1(-1)=-1[/tex]

while

[tex]\dfrac{\tan^2\pi\tan^2\frac\pi4}{1-\tan^2\pi\tan^2\frac\pi4}=\dfrac{0(1)}{1-0(1)}=0[/tex]

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