Problem:
The area of the triangle is
[tex]A\text{ = }\frac{bxh}{2}[/tex]
here, b is the base of the triangle and the variable h is its height so :
[tex]A\text{ = }\frac{bxh}{2}\text{ = }\frac{9.7\text{ in x 8.4 in}}{2}\text{ = }\frac{81.48in^2}{2}=40.74in^2[/tex]
We can conclude that the area of the shape is 40.74 in^2
