If XU is the midsegment of TVW, then, it is necessary that:
(11x + 2)/(10x + 16) = 1/2
multiply the previous equation by 10x + 16:
11x + 2 = 1/2(10x + 16)
11x + 2 = 5x + 8 subtract 5x and 2 both sides
11x - 5x = 8 - 2
6x = 6
x = 6/6
x = 1
THe length of XU is:
XU = 11x + 2 = 11(1) + 2
XU = 13
