Respuesta :

Given:-

[tex]8x+y=12[/tex]

To find x when y is 3.

So now we substitute,

[tex]\begin{gathered} 8x+y=12 \\ 8x+3=12 \\ 8x=12-3 \\ 8x=9 \\ x=\frac{9}{8} \end{gathered}[/tex]

So the value is,

[tex]\frac{9}{8}[/tex]