Let's begin by identifying key information given to us:
This is a square pyramid
Height (h) = 4 in
Base (b) = 4 in
The volume of the figure is calculated as shown below:
[tex]\begin{gathered} V=\frac{1}{3}b^2h \\ V=\frac{1}{3}\times4^2\times4 \\ V=\frac{1}{3}\times16\times4 \\ V=\frac{64}{3}=21\frac{1}{3}=21.33 \\ V=21.33in^2 \end{gathered}[/tex]
