[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$500\\ r=rate\to 4.25\%\to \frac{4.25}{100}\dotfill &0.0425\\ t=years\dotfill &10 \end{cases} \\\\\\ A=500e^{0.0425\cdot 10}\implies A=500e^{0.425}\implies A\approx 764.80[/tex]
