Respuesta :

Tucon

 

[tex]\displaystyle\bf\\\bigg(\frac{1}{\sqrt y}\bigg)^{\dfrac{-1}{5}} =\bigg(\frac{1}{\sqrt y}\bigg)^{(-\b1)\times\dfrac{1}{5}} =\sqrt{y}^{\bigg(\dfrac{1}{5}\bigg)}=\sqrt[5]{\sqrt{y}}=\boxed{\bf\sqrt[10]{y}}[/tex]