Answer:
Y = Vy t - 1/2 g t^2 height Y after time t
Y1 = -1/2 g t^2 object launched with no vertical velocity
Y2 = Vy t - 1/2 g t^2 object launched with vertical speed Vy
Obviously Y2 is greater than Y1
Y1 will reach a given negative vertical height sooner than Y2
