Answer:
the answer is "B" (thank me later) ;))
Given:- [tex]f(x)=\frac{x-3}{x+2}[/tex]
Solution:- [tex]\left(-\infty \:,\:-2\right)\cup \left(-2,\:\infty \:\right)[/tex]
So, Answer:- [tex]All \: real\: value \: of x\: such \; that \: \neq -2[/tex]
OAmalOHopeO
