Answer:
Step-by-step explanation:
TRIANGLE_AREA
[tex]A_{\Delta}=0.5*base*heigh=0.5*8ft*6ft=24ft^2[/tex]
SEMICIRCE_AREA
[tex]A=0.5*\pi r^2=0.5*\pi*(\frac{diameter}{2})^2=0.5*3.14*(\frac{10ft}{2})^2=39.25ft^2\\\\A_{tot}=24ft^2+39.25ft^2=63.25ft^2[/tex]
