Respuesta :

26jhrnje
intial velocity u=3m/s
final velocity v
2
=u
2
+2as=3
2
+(2×2×5)=29 ⟹v=5.3m/s

KE=
2
1
​
m(v
2
−u
2
)=
2
1
​
×2×((5.3)
2
−3
2
)=20J