Answer:
[tex]2x^2+16x+29[/tex]
Step-by-step explanation:
Given that,
[tex]g(x)=2x^2-5[/tex]
We need to find g(x+4)+2
[tex]g(x+4)=2(x+4)^2-5\\\\=2(x^2+16+8x)-5\\\\=2x^2+32+16x-5\\\\=2x^2+16x+27[/tex]
Now,
[tex]g(x+4)+2=2x^2+16x+27+2\\\\=2x^2+16x+29[/tex]
So, the value of [tex]g(x+4)+2[/tex] is [tex]2x^2+16x+29[/tex]
