Answer:
C
Step-by-step explanation:
[tex]f'(x)=g(x) * (x^2-4)\\0=g(x)*(x^2-4)\\x={-2,2}\\f(-4) = -\\f(-2) = 0 \\f(0) = +\\f(2) = 0 \\f(4)= -\\\\[/tex]
It decreases from negative infinity to -2, then increases, so x=-2 is a rel. min.
It increases from x=-2 to x=2, then decreases to infinity, so x=2 is a rel. max.
