Answer:
[tex]\frac{1}{2x}[/tex] , x ≠ 0
Step-by-step explanation:
Given
[tex]\frac{2x-5}{4x^2-10x}[/tex] ← factor the denominator by factoring out 2x from each term
= [tex]\frac{2x-5}{2x(2x-5)}[/tex] ← cancel the factor (2x - 5) on numerator/ denominator
= [tex]\frac{1}{2x}[/tex]
The denominator cannot be zero as this would make it undefined.
Thus x = 0 is the non- permissible value
