Respuesta :

Alfpfeu

Answer:

Step-by-step explanation:

hello,

[tex]g(x)=\dfrac{1}{x-1}\\\\x=g(g^{-1}(x))=\dfrac{1}{g^{-1}(x)-1} \\ \\g^{-1}(x)-1=\dfrac{1}{x}\\ \\g^{-1}(x)=\dfrac{1}{x}+1=\dfrac{1+x}{x}[/tex]

And this is a function defined for x different from 0.

Thanks