Answer:
F'(x) = 2x eˣ¹⁴ − eˣ⁷
Step-by-step explanation:
You're close. According to second fundamental theorem of calculus:
If F(x) = ∫ₐᵇ f(t) dt, then F'(x) = b' f(b) − a' f(a).
F(x) = ∫ₓˣ² eᵗ⁷ dt
F'(x) = (2x) e⁽ˣ²⁾⁷ − (1) e⁽ˣ⁾⁷
F'(x) = 2x eˣ¹⁴ − eˣ⁷
