Answer:
[tex]\boxed{\df \ \ \ \dfrac{b^7}{3} \ \ \ }[/tex]
Step-by-step explanation:
[tex]\dfrac{9h^2b^8}{27h^2b}=\dfrac{h^{2-2}b^{8-1}}{3}=\dfrac{b^7}{3}[/tex]
as 27=9*3
