2. [tex]x^2y^5\sqrt{x}[/tex]
3. [tex]\sqrt150}[/tex] = [tex]5\sqrt{6[/tex]
30 and 5 are viable factors for 150
30 breaks down into 5 and 6
There are two 5s left and one 6.
So, the two fives go on the outside of the radical while the 6 goes on inside.
Therefore, it would be 5[tex]\sqrt{6[/tex]
