The value of P₂ is 65.33 kPa
Explanation:
Given:
Volume, V₁ = 500mL
Pressure, P₁ = 98 kPa
Volume, V₂ = 750 mL
Pressure, P₂ = ?
According to Boyle's law:
P₁V₁ = P₂V₂
On substituting the value we get:
[tex]98 X 500 = 750 X P_2\\\\P_2 = \frac{98 X 500}{750} \\\\P_2 = 65.33 kPa[/tex]
The value of P₂ is 65.33 kPa
