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HomertheGenius
Question Q1:
Surface area of the cone:
[tex] \pi r l + \pi r^{2}=125 \pi /: \pi rl+ r^{2}=125 5l+ 5^{2}=125 5l+25=125 5l=100 l=100:5=20 [/tex]
Answer: l=20 cm.
Prettypuinkpaws15
Surface area of the cone:

Answer: l=20 cm.

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