PlainOldMe PlainOldMe

02-06-2019
Mathematics

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What are the zeros of the function? f(x)=3x^2−24x+36 Enter your answers in the boxes. The zeros of f(x) are and

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02-06-2019

[tex]

f(x)=3x^2-24x+36 \\

0=3(x-2)(x-6) \\

0=(x-2)(x-6)

[/tex]

There will be 2 solutions.

[tex]

x-2=0\Longrightarrow\boxed{x_1=2} \\

x-6=0\Longrightarrow\boxed{x_2=6}

[/tex]

Hope this helps.

r3t40

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