ANSWER
0
EXPLANATION
Given :
[tex] \frac{2a + 2}{a} = 4[/tex]
We solve for 'a' to obtain,
[tex]2a + 2 = 4a[/tex]
This implies that,
[tex]2 = 4a - 2a[/tex]
[tex]2 = 2a[/tex]
This implies that,
[tex]a = 1[/tex]
We substitute a=1 into
[tex] \frac{ 2{a}^{2} - 2}{ {a}^{2} } [/tex]
This gives us,
[tex]\frac{ 2{(1)}^{2} - 2}{ {(1)}^{2} } = \frac{2 - 2}{2} = \frac{0}{2} = 0[/tex]
