Since the line is parallel, you have the same slope: [tex]\frac{5}{6} x[/tex]
Plugging in (12,8) into [tex]y=\frac{5}{6}x+b[/tex], you get
[tex]8=\frac{5}{6} *12+b[/tex]
You get that [tex]b=-2[/tex]
Therefore, the equation is [tex]y=\frac{5}{6}x-2[/tex]
